Question

a feather is dropped onto the surface of the moon. how far will the feather have fallen if it reaches the surface in 9.00 seconds? given g: on moon is -1.63m/s2

Answer 1

\[d=v_0t+\frac{ 1 }{ 2 }at^2\]
where \(v_0=0\) and \(a=g\) so the equation becomes
\[d=\frac{ 1 }{ 2 }gt^2\]
plug in your time and gravity