Question

ΔABC is translated 6 units up and 3 units left to create ΔA′B′C′. If vertex A is located at (-1, 2), what are the coordinates of A′ ?

(5, -1)


(-4, 8)


(2, -4)


(-7, -1)

Answer 1

We have (-1, 2)
We know it goes up 6 and left 3
So:
-1 + 6 = 5
2-3 = -1
(5,-1) is your new point :D

Answer 2

that was wrong :(

Answer 3

Oh nvm I see what I did wrong /.-
I did it backwards ._.

Answer 4

-1 = x
2 = y
so:
-1 - 3 = -4
2 + 6 = 8
(-4,8)

Answer 5

Sorry...

Answer 6

(-4,8)