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log x 8 = 0.5
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One approach is to express 0.5 as a power of 8 and 3 as a power of 27. 0.5 = 2^-1 2 = 8^(1/3) So 0.5 = [8^(1/3)]^(-1) = 8^(-1/3) Thus log_8[8^(-1/3)] = -1/3. Do the other one the same way, since 3 = 27^(1/3). Another approach is to use the log conversion formula, which you might or might not have seen. log_8(0.5) = log_2(0.5)/log_2(8) = (-1)/3 In general, log_a(x) = log_b(x)/log_b(a) for any a and b.
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