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OpenStudy (anonymous):
what is the margin of error for a yes/no survey of 200 people with a proportion of 65% who answered "yes"?
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OpenStudy (anonymous):
sqrt(pq/n)
OpenStudy (anonymous):
\[\sqrt{.65(1-.65)/200}\] Didnt't know how to make the fraction look cleaner.
OpenStudy (anonymous):
\[\sqrt{.65(.35)/200}\]
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