Question

I need help solving a matrix

Answer 1

here it is

Answer 2

\[4X+A=B \\ 4X=B-A \\ X=\frac{1}{4}[B-A]\]
just find the difference of matrix B and A
then multiply by the scalar 1/4

Answer 3

Lol great name by the way.

Answer 4

\[X=\frac{ 1 }{ 4 }\left( 8 -3\right)\]

Answer 5

And so on?

Answer 6

well that would be the first entry of X
So you could say:
\[X_{11}=\frac{1}{4}(8-3)\]

Answer 7

buy yeah in general you have
\[X_{ik}=\frac{1}{4}(B_{ik}-A_{ik})\]

Answer 8

so if i'm not mistaken, one solution for X is [5/4 3/4]?

Answer 9

how do you end up with a 1 by 2 matrix?

Answer 10

oh do you mean just row 1 for X?
because X is gonna be a 3 by 2 matrix and there is only one solution for X.

Answer 11

Yeah just one row. That's all I had completed at the time. I have the rest of the answer. Thank you very much, I really appreciate your help

Answer 12

np :)