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OpenStudy (anonymous):
how do i square 21/29?
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OpenStudy (jackellyn):
\[(\frac{ 21 }{ 29})^{2} = \frac{ 21^{2} }{ 29^{2} }=?\]
OpenStudy (anonymous):
441/851
OpenStudy (anonymous):
If sin θ = , use the Pythagorean Identity to find cos θ. is my question. so i use sin^2+cos^2=1 right? so then i take 1 and subtract 441/841. i get 400/841. now what?
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