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For all real numbers n, 2n∗2n÷2n∗2=? n is the exponent
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\[2^{n} * 2^{n} \div 2^{n} * 2\]
do you need help to solve this question ?
look first rule when bases are same power will be added 2^n *2^n it will be 2^n+n 2^2n
now you need to do same thing with denominator you will get 2^n+1 now your equation will look like 2^2n / 2^n+1 as we move 2^n+1 from denominator to numerator it will be 2^-n-1
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