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Algebra 16 Online
OpenStudy (anonymous):

|x − 2| + 10 = 12

OpenStudy (anonymous):

I don't know how to slove this whats the answer

OpenStudy (anonymous):

(x-2)=2 x=4

OpenStudy (yanasidlinskiy):

Welcome to OpenStudy!!!! Chrsitina that is perfectly fine and that's why there's users who are here to help! To get started we need to isolate the "absolute value" to continue in solving. Once doing that you have a regular equation: x-2+10=10 You have same number on both sides. Combine -2 and 10 you get 8. Now your equation looks like this: x+8 = 10 Next, subtract 8 from both sides to get "X" by itself. Overall, that's what we're trying to do.. Once subtracting 8 from both sides, 8 cancels on the left which is left with x on the left side and on the right side subtracting 10-8 gives us 2. Now we clearly have found the answer. x=2 Hopefully, what I've explained above has helped you come to an understanding of how to solve these.

OpenStudy (anonymous):

Sorry yana siddlinskiy its equal to 12 not 10.

OpenStudy (irishboy123):

you have got this far i think: \(|x − 2| + 10 = 12 \implies |x-2| = 2\) now you need to sketch out y = |x-2| , remembering that |z| means absolute value of z: so, say, |-3| = 3, |10| = 10, |-33| = 33,...etc this means drawing the usual line y = x-2 *but* it will be reflected off the x axis because it is now y = |x-2| and y cannot be negative. but IMHO you need to sketch it and "see for yourself"......and you will see that there are 2 solutions.....ie there are 2 points for y = |x-2| where y = 2. you don't have to draw it, in fact you can do it in your head, but seeing it at least once in chart form makes this all very hard to forget going forward.

OpenStudy (anonymous):

well actually it can either be 4 or 0

OpenStudy (alekos):

thats right x=0 and x=4

OpenStudy (anonymous):

It could be X=0 or X=4

OpenStudy (anonymous):

@souleater @alekos right

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