***WILL FAN AND MEDAL***
Find the total area the regular pyramid.
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OpenStudy (falling_in_katt):
OpenStudy (falling_in_katt):
@sleepyhead314 @Abhisar @GenTorr
OpenStudy (sleepyhead314):
is that a regular square pyramid seen from above?
OpenStudy (falling_in_katt):
yes
OpenStudy (sleepyhead314):
do they mean surface area?
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OpenStudy (falling_in_katt):
yes
OpenStudy (sleepyhead314):
ok :)
let's first find the area of the base
that would be a square with a side length of 4
OpenStudy (sleepyhead314):
Area of a Square = (side)*(side) = 4 * 4 = ?
OpenStudy (falling_in_katt):
16
OpenStudy (sleepyhead314):
good :)
then let's find the Area of one of the Triangles :3
We need the height of it
we are given that the hypotenuse is 4
and half the base (to make a right triangle) is 2
so square root of (4^2 - 2^2) = ?
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OpenStudy (falling_in_katt):
12
OpenStudy (sleepyhead314):
square root of 12
that's right ^_^
it can be simplified to 2 squareroot of 3
then there are 4 triangles
so times 4
gives us\[\large 8\sqrt{3}\]