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Geometry 16 Online
OpenStudy (falling_in_katt):

***WILL FAN AND MEDAL*** Find the total area the regular pyramid.

OpenStudy (falling_in_katt):

OpenStudy (falling_in_katt):

@sleepyhead314 @Abhisar @GenTorr

OpenStudy (sleepyhead314):

is that a regular square pyramid seen from above?

OpenStudy (falling_in_katt):

yes

OpenStudy (sleepyhead314):

do they mean surface area?

OpenStudy (falling_in_katt):

yes

OpenStudy (sleepyhead314):

ok :) let's first find the area of the base that would be a square with a side length of 4

OpenStudy (sleepyhead314):

Area of a Square = (side)*(side) = 4 * 4 = ?

OpenStudy (falling_in_katt):

16

OpenStudy (sleepyhead314):

good :) then let's find the Area of one of the Triangles :3 We need the height of it we are given that the hypotenuse is 4 and half the base (to make a right triangle) is 2 so square root of (4^2 - 2^2) = ?

OpenStudy (falling_in_katt):

12

OpenStudy (sleepyhead314):

square root of 12 that's right ^_^ it can be simplified to 2 squareroot of 3 then there are 4 triangles so times 4 gives us\[\large 8\sqrt{3}\]

OpenStudy (sleepyhead314):

are your options in decimals? :)

OpenStudy (sleepyhead314):

we will have to add that 8 root(3) + 16

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