the area of a rectangle is 9x^2-9x-4 cm^2.

find its length and width then solve the perimeter

Am I missing something here? The roots are -1/3 and 4/3 but I can't seem to figure out how they would come out as the length & width

PLEASE HELP

Question

the area of a rectangle is 9x^2-9x-4 cm^2.

find its length and width then solve the perimeter

Am I missing something here? The roots are -1/3 and 4/3 but I can't seem to figure out how they would come out as the length & width

PLEASE HELP

alekos · Answer

from your roots that would factor out to (3x+1)(3x-4)

so what do you think the length and width would be

anonymous · Answer

-1/3 & 4/3? But one of them is negative? :(

anonymous · Answer

uhm ok so the length should be (3x+1) 

width is (3x-1)?

so i'll just substitute the 4/3 here?

anonymous · Answer

@alekos :) thanks!

alekos · Answer

no width is 3x-4

alekos · Answer

for perimeter just add l + w

anonymous · Answer

but if x = -1/3 and 4/3

3(4/3) + 1 = 5
3(4/3) - 4 = 0 ???