Question

the area of a rectangle is 9x^2-9x-4 cm^2.

find its length and width then solve the perimeter

Am I missing something here? The roots are -1/3 and 4/3 but I can't seem to figure out how they would come out as the length & width

PLEASE HELP

Answer 1

\[ 9x^2-9x-4=(3x+1)(3x-4)\\area=\frac{1}{2} base * height =(3x+1)(3x-4)\\\]can you go on ?

Answer 2

Yeah, I'm a bit stuck in this part

so the length = (3x+1)
width = (3x-4)

?

Answer 3

or should I just leave it that way, like I don't have to find the exact value? :)

Answer 4

you missed 1/2

Answer 5

base *height =2 (3x+1)(3x-4)
=(6x+2)(3x-4) or (3x+1) (6x-8)

Answer 6

base =(3x+1) height=6x-8 and viceversa

base =(6x+2) height=3x-4 and viceversa

Answer 7

but I thought the are of a rectangle is just l x w? :)

Answer 8

*area

Answer 9

oh ...i am sorry
i make it for a triangle


but it is easier now
let's do it again
h*w=(3x+1)(3x-4)

now we have to find 2(h+w)
2((3x+1)+(3x-4))

Answer 10

Ohh, okay. So those are the answers? I'll just leave it with all the x's right? :)

Answer 11

or is there a way we could find the exact values? :((

Answer 12

is there any information more ?

if not , your question is complete

Answer 13

no, nothing else. thank you so much! :)