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Mathematics 10 Online
OpenStudy (anonymous):

PLEASE HELP!! If the area of a rectangle is 16s2t and the length is 8st2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer. 2st 2 over the quantity s times t the quantity of 2 times s all over t t over the quantity 2 times s

OpenStudy (nurali):

Area=Length*Width Width=Area/Length Area=16s^2t Width=8st^2 Width=16s^2t/8st^2 Width=2s/t

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