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Solve for x. 7x - = 6x -
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thats not the question ops
\[7x-\frac{ 3 }{ 8 }= 6x - \frac{ 5 }{ 8 }\]
Don't let the fractions scare you, do the same thing as before
Collect like terms, everything with x on one side and the ones without on the other as follow \[7x-6x = -\frac{ 5 }{ 8 } + \frac{ 3 }{ 8 }\]
is it subtraction or are they negative fractions that always confuses me @Astrophysics
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Does what I said above make sense?
yes, so would it be x=1?
or 1/4?
It is -1/4
negatives confuse me
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