Question

A particle moves with velocity function v(t) = 3t^2 − 4t + 1, with v measured in feet per second and t measured in seconds. Find the acceleration of the particle at time t = 3 seconds.

Answer 1

Take the derivative and then plug in t = 3

Answer 2

\[a(t) = \frac{ dv(t) }{ dt }\]

Answer 3

So \[6t-4\] \[18-4\] \[= 14\]

Answer 4

Bingo m/s^2

Answer 5

or ft/s^2

Answer 6

Thank you!

Answer 7

Np