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if triangle ABC and triangle PQR ARE SIMILAR. FIND QR and PR. QR= PR=
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|dw:1436546792547:dw|
This problem is just like the one we did before. Use the same proportions with the new numbers to find the answer.
but its kind of different when solving it idk how to
15
\(\dfrac{AB}{PQ} = \dfrac{BC}{QR} \) \(\dfrac{3}{9} = \dfrac{5}{QR} \) \(3(QR) = 5 \times 9\) \(QR = \dfrac{5 \times 9}{3} \)
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Yes, 15 is correct for QR.
\(\dfrac{AB}{PQ} = \dfrac{AC}{PR} \) \(\dfrac{3}{9} = \dfrac{4}{PR} \) \(3(PR) = 4 \times 9\) \(PR = \dfrac{4 \times 9}{3} \)
12
Correct!
thank you
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