Question

Math question

Answer 1

A.

Answer 2

B.

Answer 3

C.

Answer 4

D.

Answer 5

hint:
we can write this identity:
\[\Large {\log _6}12 = \frac{{{{\log }_{10}}12}}{{{{\log }_{10}}6}} = \frac{{{{\log }_{10}}6 + {{\log }_{10}}2}}{{{{\log }_{10}}6}} > 1\]

Answer 6

please, keep in mind that, the solution of your equation is:
\[\Large y = {\log _6}12\]

Answer 7

So A is the answer right?

Answer 8

that's right!

Answer 9

Thanks, Michele!

Answer 10

:)