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Mathematics 8 Online
OpenStudy (anonymous):

there are 40 beads. 7/40 are yellow 5/40 are green 9/40 are blue 8/40 are brown 7/40 are orange 4/40 are red calculate WITH replacement and WITHOUT replacement for each: P(R1B2 OR B1R2) P(R1 AND G2) P(no yellows) P(doubles) P(no doubles)

OpenStudy (nincompoop):

where is your attempt?

OpenStudy (anonymous):

oh okay so for the or situation would it be like 2/1600 + 2/1600

OpenStudy (triciaal):

B = blue or brown

OpenStudy (anonymous):

or B is Brown!!

OpenStudy (anonymous):

*oh

OpenStudy (triciaal):

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