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Algebra 23 Online
OpenStudy (anonymous):

solve for C. a = b + c/d a.) c=ad-b b.) c= a+b/d c.) c=ad/b d.) c= ab+d

OpenStudy (anonymous):

What do you think?

OpenStudy (anonymous):

\( \huge a = \frac{b + c}{d} \) \( \huge d\times a = \frac{b + c}{d} \times d \) \( \huge da = b + c \) \( \huge da-b = c \) \( \huge c = da-b \)

OpenStudy (anonymous):

I was reading that wrong XD cause your b+c didn't have a bracket

OpenStudy (anonymous):

\( \huge c = da-b \) OR \( \huge c = ad-b \)

OpenStudy (usukidoll):

@Nixy good job! :)

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