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problem is in the comments. please help.
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\[A(t)=300(1+\frac{.04}{12})^{12(8)}\]
Grind it out.
29109
no
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What is .04/12 ???
.003
Add 1 to that
1.003
1.0033333333333333
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Raise that to the power of 8 times12 which is 96
96*300
\[A(t)=300(1+.0033333333333)^{96}\]
\[A(t)=300(1.00333333333333)^{96}\]
so you get D?
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\[A(t)=300(1.376395119233)\]
\[A(t)=412.92\]
thank you so much. c:
yw
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