Question

A student solved the following problem and made an error:

Answer 1

Line 1 segment AC equals 2, segment DF equals 2, segment AC is congruent to segment DF
Line 2 ∠A ≅ ∠F
Line 3 Length of segment AB.
A (0, 2)
B (2, 4)
d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, then d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, then d equals square root of negative 2 squared plus negative 2 squared, then d equals square root of 4 plus 4, then d equals square root of 8
segment AB = 2.83
Line 4 Length of segment FD.
D (2, 0)
F (4, 2)
d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared then d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 2 all squared, then d equals square root of negative 2 squared plus negative 2 squared, then d equals square root of 4 plus 4, then d equals square root of 8
segment FD = 2.83
Line 5 segment AC is congruent to segment FD
Line 6 triangle ABC is congruent to triangle FDE by SAS

Answer 2

In which line did the student make the first mistake?
Line 3
Line 5
Line 1
Line 2

Answer 3

Woah

Answer 4

I agree @sunleaf01

Answer 5

@SomeoneHelpPlz What is the student trying to prove?