Because of the rainy season, the depth in a pond increases 3% each week. Before the rainy season started, the pond was 10 feet deep. What is the function that best represents the depth of the pond each week and how deep is the pond after 8 weeks? Round your answer to the nearest foot.
Hint: Use the formula, f(x) = P(1 + r)x.

f(x) = 10(0.03)x, 36 feet
f(x) = 10(1.03)x, 14 feet
f(x) = 10(1.3)x, 37 feet
f(x) = 10(1.03)x, 13 feet

Question

Because of the rainy season, the depth in a pond increases 3% each week. Before the rainy season started, the pond was 10 feet deep. What is the function that best represents the depth of the pond each week and how deep is the pond after 8 weeks? Round your answer to the nearest foot.
Hint: Use the formula, f(x) = P(1 + r)x.

 f(x) = 10(0.03)x, 36 feet
 f(x) = 10(1.03)x, 14 feet
 f(x) = 10(1.3)x, 37 feet
 f(x) = 10(1.03)x, 13 feet

anonymous · Answer

What do you think it is? @Jbeezy112

anonymous · Answer

last option is correct f(x) = 10(1.03)x where x is the number of time intervals that have passed r is growth rate,since r is given in percentage so we will divide 3 by 100 you can solve it like this
$$f(x)=10(1+0.03)^{8}$$

anonymous · Answer

x should be the power of term (1+r)