Question

What is the equation of the tangent line passing through the point (0, 3) of the graph of the function f(x) = x^2 − 2x + 3?

y = –2x + 3

y = 3x + 1

y = 2x − 3

y = –3x + 3

Answer 1

here we have to apply this formula:
\[\Large y - 3 = f'\left( 0 \right)\left( {x - 0} \right)\]

Answer 2

where f ' (0) is the first derivative of your function at point x=0