Question

Find the equation of the line tangent to y = –x2 + 3x + 8 at x = 2.

Answer 1

@dan815 could you help me?

Answer 2

the derivative formula that I got is f'(x)= -6x+1

Answer 3

but none of the answers match my answer

Answer 4

Find the equation of the line tangent to y = –x2 + 3x + 8 at x = 2.

y = –2x + 2
y = –x + 12
y = –x + 2
y = –2x – 12