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OpenStudy (anonymous):
What is the length of the focal width? x=\ -\frac{1}{8}y^2
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OpenStudy (anonymous):
sorry, the equation got messed up. It's \[x=\ -\frac{1}{8}y^2\]
OpenStudy (jacob902):
Direction : Opens Left Vertex :(0,0) Focus :(−2,0) Axis of Symmetry :y=0 Directrix :x=2 x−2−10y−4−2.830
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