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If T -1 (x, y) (½x, y - 5), then T(x, y)
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your question is not clear !
do you mean ?\[T^{-1}(x,y)=(\frac{1}{2}x,y-6) \\tT =?\]
\[\frac{1}{2}x=X \rightarrow x=2X\\y-5=Y \rightarrow y=Y+5 \\so\\T(x,y)=(2X,y+5)\]
Thank youuuuu
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what about this one
(x,y)=(x+3,y-2) because t(0,2)=(0+3,2-2) so find T-1
can you do like ,previous problem ?
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