Question

-------- WILL MEDAL --------
-------- HELP PLEASE --------
Find the x-intercepts for the parabola defined by the equation below.

y = x^2 + x - 12

Answer 1

@Nixy i got (-4,0) and (3,0)

Answer 2

x-intercepts are when y = 0

x^2 + x - 12 = 0
*factorise*
(x - 3) ( x + 4) = 0
x = 3, -4

Therefore x-intercepts are at: (3, 0) and ( -4, 0)
Sooo, you're correct :) excellent work :D!