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Solve for x: (x+4)/3= 2
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We flip the fraction an multiply by the reciporcal \[\huge~\rm~\frac{ x+4 }{ 3 }\times (3) = (2) \times(3)\]
6
good and the 3's cancel out so we get \[\huge~\rm~x+4=6\] from here solve for x
x=2?
yep :)
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yay :) thnx :)
:)
x=2
you can recheck the answer by putting the value of x in the equation. if LHS=RHS then its correct :)
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