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What is the probability of 2 successes in 4 trials of an experiment if the probability of success of one trial is 0.3?
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.15 because .5*.3=.15
15%
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The binomial distribution applies to this. Therefore the required probability is given by \[\large P(2\ out\ of\ 4)=4C2\times0.3^{2}\times0.7^{2}=0.2646\]
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