Question

Solve this using pascal's triangle (2x+3)^5

Answer 1

@misssunshinexxoxo

Answer 2

\((2x+3)^5\)

First write out the polynomial without the coefficients. i.e. without the triangle part yet

\((2x)^5+(2x)^43+(2x)^33^2+(2x)^23^3+(2x)3^4+3^5\)

Then use the triangle to get the coefficients

\(32(2x)^5+5*32(2x)^43+\frac{4*5*32}{2}(2x)^33^2+\frac{4*5*32}{2}(2x)^23^3+5*32(2x)3^4+3^5\)