What is the equation of a circle with center (-3, -1) that contains the point (1, 2)?
A. (x + 3)2 + (y + 1)2 = 25
B. (x − 3)2 + (y − 1)2 = 36
C. (x + 3)2 + (y − 1)2 = 36
D. (x − 1)2 + (y − 2)2 = 25

Question

What is the equation of a circle with center (-3, -1) that contains the point (1, 2)?
A. (x + 3)2 + (y + 1)2 = 25
B. (x − 3)2 + (y − 1)2 = 36
C. (x + 3)2 + (y − 1)2 = 36
D. (x − 1)2 + (y − 2)2 = 25

anonymous · Answer

$$equation\ of \ circle \ with \ center \ (a,b) \ radius\ r \ \ and\ general \  points \ (x,y) \ on \ circumference \ = (x-a)^2 + (y-b)^2= r^2 \ here \ (a,b) = (-3,-1) \ r^2= (-3-1)^2+(-1-2)^2=25\therefore \  equation \  of \ circle \ is \ [x-(-3)]^2+[y-(-1)]^2=25 \ [x+3]^2+[y+1]^2=25$$
Hence option A is correct.

anonymous · Answer

figured that was the answer, ^-^ thanks