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The estimated probability of a bowler getting a strike during a particular frame is 63%. If several simulations of the bowler bowling two frames were performed, in what percentage of the simulations would the bowler be most likely to get a strike in each of the two frames? A. 81% B. 38% C. 18% D. 61%
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will medal
probability of two strikes = (probability of one strike)*(probability of one strike) = (0.63)*(0.63)
but thats not one of the answers?
multiply (0.63)*(0.63)
still dont get the answer?
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i got 0.3969?
which is the closest to...?
hint: question asks for "most likely"
is it B?
right
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