Question

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Answer 1

dy/dx = dy/dt * dt/dx

Answer 2

dt /dx = 1 / dx/dt = 1/3

Answer 3

and can you find dy/dx from y = 3x^3 - 2x ?

Answer 4

9x^2-2?

Answer 5

right
x = -2
so we have
9(-2)^2 - 2 = dy/dt * 1/3
34 = dy/dt / 3

dy/dt = ?

Answer 6

cross multiply

Answer 7

102?

Answer 8

right

Answer 9

Thank you!!!

Answer 10

yw