Question

Find a cubic function with the given zeros.
6, -5, 2

How would I solve this?

Answer 1

\(\large {
x=\{6, -5, 2\}\implies
\begin{cases}
x=6\to &x-6=0\\
x=-5\to &x+5=0\\
x=2\to &x-2=0
\end{cases}
\\ \quad \\
(x-6)(x+5)(x-2)=\textit{original polynomial}
}\)

Answer 2

3 values for "x", means, 3 factors in this case, and thus a 3rd degree polynomial or namely a "cubic"

Answer 3

Thank you.

Answer 4

how would i solve it? go to reverse.