Question

for the simple harmonic motion equation d=9 cos(pi/2t) what is the period?

Answer 1

is it 1?

Answer 2

HI!!

Answer 3

period of \(\cos(bx)\) is \[\frac{2\pi}{b}\]

Answer 4

so no, it is not one

Answer 5

so 2pi/b?

Answer 6

lol no dear, you need a number out of this
in your case \(b=\frac{\pi}{2}\) so divide \(2\pi\) by \(\frac{\pi}{2}\)

Answer 7

4?

Answer 8

yes four !

Answer 9

So then 4 would be the period?

Answer 10

yes 4 would be the period

Answer 11

Thank you!:)

Answer 12

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