Question

Find the difference. (4x2 + 3x + 2) - (2x2 + 2x + 1)
A. 2x2 + 5x + 3
B. 2x2 + x + 1
C. 2x2 - x - 1
how do i do this? i totally forgot

Answer 1

Quite easy. This is just like a normal subtraction problem, except with variables.

Answer 2

So we have \[(4x^2 + 3x + 2) - (2x^2 + 2x + 1)\]

So this is essentially; \[(4x2 + 3x + 2) - 1 (2x2 + 2x + 1)\]

Answer 3

You would distribute the negative one,

so \[4x^2+3x+2− 2x^2- 2x-1\]

Answer 4

Then combine like terms.

\[2x^2 + x +1\]