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Chemistry 19 Online
OpenStudy (anonymous):

Show how the volume of a 0.450 mol L-1 HCl is needed to react completely with 50 ml 0.202 molL-1 of sodium carbonate

OpenStudy (anonymous):

Could you hep @peachpi

OpenStudy (anonymous):

Is it suppose to be mol/L ?

OpenStudy (anonymous):

Have you set up the reaction?

OpenStudy (anonymous):

Hello??

OpenStudy (anonymous):

yes i guess so @Deeezzzz

OpenStudy (anonymous):

I think it is mol/L

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