Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

(FAN AND MEDAL) The following table shows the expressions that represent the sales of 4 companies: Company A B C D Sales 340(1.03)x 275(0.89)x 180(1.23)x 260(1.90)x

OpenStudy (anonymous):

Rank the company sales by smallest to largest percent of increase and select the correct answer below. A)A, B, C, D B)A, D, B, C C)B, A, C, D D)C, B, D, A

OpenStudy (anonymous):

@Michele_Laino can you help me???

OpenStudy (anonymous):

@DanJS @amoodarya @peachpi ???

OpenStudy (anonymous):

i need help please

OpenStudy (amoodarya):

do you mean ? \[340(1.03)^x \\275(0.89)^x \\180(1.23)^x \\260(1.90)^x\]

OpenStudy (anonymous):

yes

OpenStudy (amoodarya):

ok so note that \[if\\a>b>c>d>0\\x>o\\a^x>b^x>c^x>d^x\]

OpenStudy (anonymous):

so, what i need to do now?

OpenStudy (amoodarya):

which base is largest ?

OpenStudy (anonymous):

i tink the first one

OpenStudy (anonymous):

@amoodarya ???

OpenStudy (anonymous):

@jim_thompson5910 ???

OpenStudy (amoodarya):

coefficient is not important base is i m p o r t an t

jimthompson5910 (jim_thompson5910):

Bases are marked in \(\color{red}{\text{red}}\) \[340({\color{red}{1.03}})^x \\275({\color{red}{0.89}})^x \\180({\color{red}{1.23}})^x \\260({\color{red}{1.90}})^x\]

OpenStudy (amoodarya):

\[340(1.03)^x\\275(0.89)^x\\180(1.23)^x\\260(1.90)^x\\1.9 >1.23>1.03>0.89\\so \\260(1.90)^x >180(1.23)^x >340(1.03)^ >275(0.89)^xx\]

OpenStudy (anonymous):

so the asnwer its B? i'm right?

OpenStudy (anonymous):

oh no my bad

OpenStudy (amoodarya):

b is smallest

OpenStudy (anonymous):

its A or C? RIGHT?

jimthompson5910 (jim_thompson5910):

@EmilyF03 what do you get when you sort these numbers (smallest to biggest) 1.03, 0.89, 1.23, 1.90

OpenStudy (amoodarya):

again note that B is smallest so ...?

OpenStudy (amoodarya):

OpenStudy (amoodarya):

look this pic make a sense

OpenStudy (anonymous):

Yup

OpenStudy (amoodarya):

make a sense ?

OpenStudy (anonymous):

yes

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!