Question

Factor: x2 + 11x + 10

a: (x + 10)(x +1)
b: (x + 11)(x + 10)
c: (x + 2)(x + 5)
d: prime

Answer 1

To factor
\[x^2+11x+10 \]
we have to focus on the middle term and the last term
so our last term is 10, and we have to list all possibilities of multiplication of 10
so our choices would be
1 x 10 = 10
2 x 5 = 10

then based on the middle term we use addition and only one pair of numbers work

Answer 2

ok

Answer 3

so what's 1+10?
what's 2+5 ?

Answer 4

11 and 7

Answer 5

prime?

Answer 6

ah! We found our 11
because 10+1 = 11
10 x 1 = 10
so since we have found or numbers we can factor

Answer 7

ok

Answer 8

since your quadratic equation is all positive signs, we don't have to worry about sign combinations

Answer 9

so we have
(x+ ?)(x + ? )
fill in those ?
using the information I've typed earlier

Answer 10

x+11

Answer 11

close xD

"We found our 11
because 10+1 = 11"

Answer 12

x+10?

Answer 13

no.. remember those 2 digital 10 and 1 that produced 11?
write those down
(x+?)(x+?)

Answer 14

wut did I just type .. it's 2 numbers 10 and 1 =_=

Answer 15

5+2

Answer 16

no now we're going backwards
5+2 is 7 and it doesn't match the middle term which is 11 so we throw that combination out

Answer 17

then i don't know

Answer 18

:/ we found our combination
10 x 1 = 10 which matches the last term
10 + 1 = 11 matches the middle term
what numbers did I just use to make 10 and 11 ?

Answer 19

1

Answer 20

yeah that was one of the numbers.
(x+1)(x+?) what was the other number?

Answer 21

was it 2?

Answer 22

no

Answer 23

and 10

Answer 24

yes!
(x+1)(x+10)

Answer 25

thanks

Answer 26

and you can check by using the FOIL method
(x+1)(x+10) = x^2+10x+x+10 =x^2+11x+10

Answer 27

so is that the final answer?

Answer 28

yeah