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Mathematics 9 Online
OpenStudy (anonymous):

√(x-y)+m=d √(x-99)+4=20 √(x-99)=16 (√(x-99))^2=16^2 x-99=256 +99 +99 X = 355 How do I figure out if this is extraneous or not?

OpenStudy (anonymous):

put 355 in for x in the original. If it makes the equation true it's a solution. If it makes it false it's extraneous

OpenStudy (anonymous):

@peachpi thank you!

OpenStudy (anonymous):

you're welcome

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