Question

for the equation 2x+3y=18, find the missing value of the following ordered pairs
(3,?)
(-6,?)
(0,?)
(?,0)

Answer 1

plug 3 for x
2*3+3y=18
3*2=6
subtract 18-6 = 12
3y = 12
divide by 3
y = 4
so the missing number for the first ordered pair is 4

Answer 2

now we do the same for the rest

Answer 3

plug -6 for x
\(2*(-6)+3y=18\)

what's 2*(-6)?

Answer 4

@uju25 ?

Answer 5

thanks so much

Answer 6

2*(-6) = -12