Question

simplify: sec(x)-tan(x)sin(x)+(sin(2x))/(2sin(x))

Answer 1

\[\sec \theta-\tan \theta \sin+\frac{ \sin(2\theta) }{ 2\sin(\theta) }\]

Answer 2

\[\frac{1}{\cos \theta}-\frac{\sin \theta}{\cos \theta}\times \sin \theta+\frac{2\sin \theta \cos \theta}{2\sin \theta}=\]

Answer 3

answer choices are:
a)cos(x)^2
b)2cos(x)
c)sin(x)+1
d)cos(x)+1
e)2sin(x)

Answer 4

\[\[\frac{1-\sin ^2\theta}{\cos \theta}+\cos \theta=\frac{\cos ^2\theta}{\cos \theta}+\cos \theta =\cos \theta +\cos \theta =\]

Answer 5

\[2 \cos \theta\]

Answer 6

@Mertsj Thanks so much!

Answer 7

yw