Question

Solve: 1-sin(2πt)=0, for 0≤t≤2.

Answer 1

we have:
\[\Large \sin \left( {2\pi t} \right) = 1\]

Answer 2

now:
sin x= 1
when:
\[x = \frac{\pi }{2},2\pi + \frac{\pi }{2},4\pi + \frac{\pi }{2}...\]

Answer 3

for example, for the first solution, pi/2, we can write:
\[2\pi t = \frac{\pi }{2}\]
please solve for t

Answer 4

t=2π?

Answer 5

no try again

Answer 6

t=π^2?