Divide Anyone want to help me out? x^2 -4/x-8/x-2 A.(x-2)(x+2)/x -8 B.x-8/x+2 <-- This is wrong C.x-2/x-8 D.x+2/x-8 I think it is C i'm just being for sure I failed math the first time trying not to do that again. XD
is it \[\huge\rm \frac{ \frac{ x^2 -4}{ x-8 } }{ x-2 }\]
Yes it is.
alright show your work plz
or explain how did you get C ?
To be honest guess it XD
i knew it don't guess and btw it's too hard to pick the option whn there are 4!
I Know but if you don't know how to solve it it's the next option.
\[\huge\rm \frac{ \frac{ x^2 -4}{ x-8 } }{ x-2 }\] first of all change division the multiplication so multiply first fraction by the reciprocal of the bottom fraction example \[\large\rm \frac{ \frac{ a }{ b } }{ \frac{ c }{ d }}\] \[\bf \frac{ a }{ b } \times \frac{ d }{ c }\]
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