Question

Factoring and using the quadratic formula:
2y^2-3y-6=0

Answer 1

Do you know what the quadratic formula is?

Answer 2

using quadratic formula
y=1+/-(1+4*2*6)^1/2 whole divided by 2.2
y=-3/2 and 2
y=

Answer 3

using factorization
2y^2-y-6=0
2y^2-4y+3y-6=0
2y(y-2)+3(y-2)=0
(2y+3)(y-2)=0
answer=-3/2&2

Answer 4

This is my best answer (2y+3)(y-2)

Answer 5

2y² - y - 6 = 0

y = [1±√ (1 + 4 x 2 x 6)] / 4

y = [ 1± √49 ] / 4

y = 8/4 or -6/4

y = 2 or - 3/2

Can be checked by factorising:-

2y² - y - 6 = 0

(2y + 3).(y - 2) = 0

y = - 3/2 or y = 2 --------------(as above)