Question

Find all solutions to the equation.

7 sin2x - 14 sin x + 2 = -5

Answer 1

same set it equal to zero you will get quadratic equation \[\huge\rm Ax^2 + Bx+C =0\]

Answer 2

so..
7x^2-14x+2 = -5 then set it equal to zero by adding 5 to both sides.
then factoring
7(x^2-2x+1) = 0
factor again
7(x-1)(x-1) = 0
so
x = 1 with a multiplicity of 2?

Answer 3

oh nvm it's

Answer 4

yes right so now you can replace x by sin
(sinx - 1)(sin x -1)= 0

so sin x =1 sin x = 1

Answer 5

and \[7 \cancel{=} 0\]