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Two metal balls have charges of 7.1 * 10ÈÒ coulombs and 6.9 * 10ÈÒ coulombs. They are 5.7 * 10ȹ meters apart. What is the force of interaction between the two balls? (k = 9.0 * 10© newton·metersÆ/coulombÆ) a. 5.7 newtons b. 6.9 newtons c. 7.1 newtons d. 1.4 newton
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use Coulombs law: \( \large F = k \frac{q_1 \ q_2}{r^2} \)
can you just help me out with the answer? @IrishBoy123
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