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OpenStudy (anonymous):
how do you factor this completely? 6h^2 + 17h - 14
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OpenStudy (anonymous):
\[(2 h+7) (3 h-2) \]
OpenStudy (campbell_st):
well this is the method I use for a quadratic \[ax^2 + bx + c = 0\] multiply a and c so you need to multiply 6 and -14 6*-14 = -84 then find the factors that add to b, 17 you need to know the larger factor is positive and the smaller is negative... can you do that..?
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