Question

How to find the major and minor axis in the equation x^2+4y^2=36

Answer 1

\( \large x^2+4y^2=36\)

\( \large \frac {x^2}{36} + \frac{4 y^2}{36} = 1\)

\( \large (\frac {x}{6})^2 + (\frac{ y}{3})^2 = 1\)