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OpenStudy (anonymous):
Find S25 for 3+7+11+15
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OpenStudy (anonymous):
Let \(a_1=3\), \(d=7-3=4\) and \(n=25\). Since this is an arithmetic series, we have \[S_{25}=\frac{n}{2}[2a_1+(n-1)d]=\frac{25}{2}[2(3)+(25-1)4]=\boxed{1275}\]
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