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Mathematics 19 Online
OpenStudy (anonymous):

At a high school, 18% of all students are in the school musical and the choir, and 32% of all students are in the school musical. What is the probability that a student is in choir, given that the student is in the school musical? The person who helps me answer this gets a medal and a fan!!!

OpenStudy (anonymous):

please can anybody help me!!

OpenStudy (anonymous):

@Vocaloid could you help me

OpenStudy (snivvles.com):

im here

OpenStudy (snivvles.com):

50%

OpenStudy (anonymous):

ok yes and you too i didn't see your icon so i thought you were offline

OpenStudy (snivvles.com):

the answer is 50%

OpenStudy (anonymous):

50 is not an option

OpenStudy (snivvles.com):

oops wrong question... heh heh helping multiple people is hard

OpenStudy (anonymous):

its fine thank you for helping people who have a difficult time in math

OpenStudy (snivvles.com):

Pr(C|M)=Pr(M∩C)/Pr(M)

OpenStudy (snivvles.com):

C in choir M in musical

OpenStudy (snivvles.com):

M∩C in both choir and musical C|M in choir given they are in musical

OpenStudy (anonymous):

what does that sign down u stand for; can i get it on my calculator ti84 plus

OpenStudy (snivvles.com):

|dw:1437607735000:dw|

OpenStudy (snivvles.com):

it's where they both happen

OpenStudy (anonymous):

ok so is it 18x32/32

OpenStudy (anonymous):

I'm sorry i am kind of mind numbing i have been doing math for i swear 6 hours straight of practice tests.

OpenStudy (snivvles.com):

um...

OpenStudy (snivvles.com):

im blanking on this now

OpenStudy (anonymous):

yeh but i think its fourteen for some reason

OpenStudy (snivvles.com):

@Mertsj

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